27=t+1/2(9.8t^2)

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Solution for 27=t+1/2(9.8t^2) equation: 



27=t+1/2(9.8t^2)

We move all terms to the left:

27-(t+1/2(9.8t^2))=0



Domain of the equation: 2(9.8t^2))!=0

t∈R



We multiply all the terms by the denominator


-(t+1+27*2(9.8t^2))=0



We calculate terms in parentheses: -(t+1+27*2(9.8t^2)), so:

t+1+27*2(9.8t^2)

determiningTheFunctionDomain
t+27*2(9.8t^2)+1

Wy multiply elements

t+54t(9+1

Back to the equation:

-(t+54t(9+1)



We add all the numbers together, and all the variables

-(t+54t10=0

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